Add UE1 A.2
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@ -1,3 +1,7 @@
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FROM haskell:buster
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RUN apt-get update && apt-get install -y haskell-platform
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WORKDIR /opt
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CMD ["ghci"]
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@ -16,9 +16,6 @@ type Zerlegungszeugen = [Zerlegungszeuge]
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-- Aufgabe A.1
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ist_tzr :: Zeichenreihe -> Teilzeichenreihe -> IstTeilzeichenreihe
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{-
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Solution:
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- if both strings are the same, True
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@ -29,26 +26,49 @@ ist_tzr :: Zeichenreihe -> Teilzeichenreihe -> IstTeilzeichenreihe
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If it is not, the first string will get smaller than the second eventually and the function will return False
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-}
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ist_tzr x y
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| y == x = True
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| y == [] = True
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| length y > length x = False
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ist_tzr :: Zeichenreihe -> Teilzeichenreihe -> IstTeilzeichenreihe
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ist_tzr z t
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| t == z = True
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| t == [] = True
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| length t > length z = False
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| otherwise =
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if head x == head y then
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ist_tzr (tail x) (tail y)
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if head z == head t then
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ist_tzr (tail z) (tail t)
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else
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ist_tzr (tail x) y
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ist_tzr (tail z) t
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-- Aufgabe A.2
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--tzr_zeuge :: Zeichenreihe -> Teilzeichenreihe -> Zerlegungszeuge
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{- Knapp, aber gut nachvollziehbar geht tzr_zeuge folgendermassen vor:
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...
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{-
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Solution:
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- the base cases are as follows:
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- both strings are empty, return a triple with empty strings
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- the second string is empty, return a triple with empty strings as first two elements and the whole first string as a third.
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The problem description states that the split doesn't matter, so we take this because it is easy and cheap to do :)
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- the second string is not a subset of the first string, return the "error triple"
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- for handling the other cases:
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- we find the position of the last subset string in the first string
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- we take all of the characters until this position - this is the first element of the triple
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- we then take all of the characters after this position summed with the length of the second string - this is the third element of the triple
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-}
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tzr_zeuge :: Zeichenreihe -> Teilzeichenreihe -> Zerlegungszeuge
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tzr_zeuge [] [] = ("", "", "")
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tzr_zeuge z [] = ("", "", z)
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tzr_zeuge z t
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| not (ist_tzr z t) = ("", t ++ t, "")
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| otherwise =
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let pos = (find_tzr_position z t 0) - 1
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pre = take (pos) z
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suf = drop (pos + (length t)) z
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in (pre, t, suf)
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-- find the index of the last occurrence of t in z
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find_tzr_position :: Zeichenreihe -> Teilzeichenreihe -> Nat0 -> Nat0
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find_tzr_position (z:zs) t n
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| not (ist_tzr (z:zs) t) = n
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| otherwise = find_tzr_position zs t (n + 1)
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-- Aufgabe A.3
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--tzr_zeugen :: Zeichenreihe -> Teilzeichenreihe -> Zerlegungszeugen
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@ -65,7 +85,3 @@ ist_tzr x y
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{- Knapp, aber gut nachvollziehbar geht wieOft folgendermassen vor:
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...
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-}
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